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35r^2=-17r-2
We move all terms to the left:
35r^2-(-17r-2)=0
We get rid of parentheses
35r^2+17r+2=0
a = 35; b = 17; c = +2;
Δ = b2-4ac
Δ = 172-4·35·2
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-3}{2*35}=\frac{-20}{70} =-2/7 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+3}{2*35}=\frac{-14}{70} =-1/5 $
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